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Mathematics 14 Online
OpenStudy (anonymous):

Describe the solutions to the quadratic equation below: http://i.imgur.com/vZrnU3J.png 1 rational (double) root 2 rational roots 2 irrational roots 2 complex roots

Directrix (directrix):

You can solve the quadratic and look at the roots to decide. Or, you can find the discriminant and use it to decide. See attachments.

OpenStudy (anonymous):

So it would be c?

Directrix (directrix):

Let me crank it out. Just a moment.

Directrix (directrix):

If this is c: --> 2 irrational roots --> then No.

Directrix (directrix):

Look at the quadratic: x^2 + 6x + 9 = 0 It factors: (x + 3)* (x + 3) = 0 @ShantelT1 What are the two solutions?

OpenStudy (anonymous):

i dont know :(

Directrix (directrix):

Yes, you do. Look: (x + 3)* (x + 3) = 0 x + 3 = 0 OR x + 3 = 0 x = ? OR x = ?

Directrix (directrix):

What added to 3 gives a sum of zero?

OpenStudy (anonymous):

3

Directrix (directrix):

3 + 3 = 6, not zero. Try again. What added to 3 gives a sum of zero?

OpenStudy (anonymous):

-3

Directrix (directrix):

x + 3 = 0 OR x + 3 = 0 x = -3 OR x = -3 So, which option is this?

Directrix (directrix):

-3 is considered to be a double root.

OpenStudy (anonymous):

So it's 1 ratopma;?

OpenStudy (anonymous):

Rational*

Directrix (directrix):

1 rational (double) root Yes.

OpenStudy (anonymous):

ty

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