Describe the solutions to the quadratic equation below: http://i.imgur.com/vZrnU3J.png 1 rational (double) root 2 rational roots 2 irrational roots 2 complex roots
You can solve the quadratic and look at the roots to decide. Or, you can find the discriminant and use it to decide. See attachments.
So it would be c?
Let me crank it out. Just a moment.
If this is c: --> 2 irrational roots --> then No.
Look at the quadratic: x^2 + 6x + 9 = 0 It factors: (x + 3)* (x + 3) = 0 @ShantelT1 What are the two solutions?
i dont know :(
Yes, you do. Look: (x + 3)* (x + 3) = 0 x + 3 = 0 OR x + 3 = 0 x = ? OR x = ?
What added to 3 gives a sum of zero?
3
3 + 3 = 6, not zero. Try again. What added to 3 gives a sum of zero?
-3
x + 3 = 0 OR x + 3 = 0 x = -3 OR x = -3 So, which option is this?
-3 is considered to be a double root.
So it's 1 ratopma;?
Rational*
1 rational (double) root Yes.
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