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OpenStudy (anonymous):
Describe the solutions to the quadratic equation below:
http://i.imgur.com/vZrnU3J.png
1 rational (double) root
2 rational roots
2 irrational roots
2 complex roots
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Directrix (directrix):
You can solve the quadratic and look at the roots to decide.
Or, you can find the discriminant and use it to decide.
See attachments.
OpenStudy (anonymous):
So it would be c?
Directrix (directrix):
Let me crank it out. Just a moment.
Directrix (directrix):
If this is c: --> 2 irrational roots --> then No.
Directrix (directrix):
Look at the quadratic:
x^2 + 6x + 9 = 0
It factors:
(x + 3)* (x + 3) = 0
@ShantelT1 What are the two solutions?
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OpenStudy (anonymous):
i dont know :(
Directrix (directrix):
Yes, you do.
Look:
(x + 3)* (x + 3) = 0
x + 3 = 0 OR x + 3 = 0
x = ? OR x = ?
Directrix (directrix):
What added to 3 gives a sum of zero?
OpenStudy (anonymous):
3
Directrix (directrix):
3 + 3 = 6, not zero.
Try again.
What added to 3 gives a sum of zero?
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OpenStudy (anonymous):
-3
Directrix (directrix):
x + 3 = 0 OR x + 3 = 0
x = -3 OR x = -3
So, which option is this?
Directrix (directrix):
-3 is considered to be a double root.
OpenStudy (anonymous):
So it's 1 ratopma;?
OpenStudy (anonymous):
Rational*
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Directrix (directrix):
1 rational (double) root Yes.
OpenStudy (anonymous):
ty
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