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log base √a of a^2
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Hint: \(\large a^2 = (\sqrt{a})^4\). Thus, \(\large \log_{\sqrt{a}}(a^2) = \log_{\sqrt{a}}((\sqrt{a})^4) = \ldots\). Can you proceed from here? :-)
Give me some time to think this through.Thanks
No problem. Another possible approach (which might be simpler) is to suppose that \(\large \log_{\sqrt{a}}(a^2)= x\) and then rewrite this in exponential form as follows: \(\large \large (\sqrt{a})^x = a^2\) and then solve for x. Either way, you'll get the same answer. I hope this makes sense! :-)
Yes,the second one seems easier.I guess I'll try both.Thank you so much :)
No problem. Glad to be of assistance. :-)
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