A company builds computers. It costs $7,600 to build 10 computers and $12,200 to build 20 computers. Which equation models the cost, C(x), as a linear function of the number of computers built, x?

C(x) = 460x − 3000

C(x) = 3000x − 460

C(x) = 460x + 3000

C(x) = 3000x + 460

Question

A company builds computers. It costs $7,600 to build 10 computers and $12,200 to build 20 computers. Which equation models the cost, C(x), as a linear function of the number of computers built, x?

 C(x) = 460x − 3000

 C(x) = 3000x − 460

 C(x) = 460x + 3000

 C(x) = 3000x + 460

anonymous · Answer

you can consider this as equation of a line... where x will be the horizontal axis representing the number of computers built and x > 0...

anonymous · Answer

i'm confused :( i think it's c or d

anonymous · Answer

you can check it by plugging in the given points... that is if x=10, C(x)=$7,600 and when x=20 then C(x)=$12,200...

anonymous · Answer

Ok but I am still confused on why did they put the same answer but backwards for c and d i don't know which order it's suppose to be in

anonymous · Answer

if we look at c... we got the correct given points

anonymous · Answer

if we go on d... we multiply 3000 by 10x = 30,000 and that is more than 7600...

anonymous · Answer

much more when 3000 x 20 = 60,000 > 12,200... therefore it did not satisfy the given points...

anonymous · Answer

so c is the correct relationship... :)

anonymous · Answer

Ohh thank you so much

anonymous · Answer

no problem... :)