Question

help ?!!??!?!?
Pappy's Pond is located close to an elementary school. The city plans to fence it in to keep small children from accessing the water. What is the perimeter of a triangular-shaped fence the city can place around the pond using integer coordinates (no decimals) on the grid? You must show all work to receive credit.

Answer 1

@rajat97 help plz

Answer 2

yup i'm on it

Answer 3

thinking hw to do this

Answer 4

any ideas??

Answer 5

nope

Answer 6

@phi @amistre64 can u guys help

Answer 7

i think there's no specific method for solving this problem so i'll go with assumptions

Answer 8

since its not asking for a minimum perimeter you just have to create a triangle and determine its specific perimeter

Answer 9

if we go 10 up and 10 out ... we encase the pond ...

Answer 10

yes i think you are right @amistre64 and i was gonna do that in the same way:)

Answer 11

:)

Answer 12

i think we shall first make assumptions for the co-ordinates of the points as no specific perimeter is asked and make sure that the line is always above the pond and not intersecting it
so i've some suggestions here
take one point say R (1,0)
another one A (1,7) and another one
J (0,12) all the points are taken by observation if you doubt these points, you can take a scale and then see if any of the segments made from these points intersect the pond or not
so by using the distance formula for all these points , you get the perimeter 38.026 units
or if you do not open the square root , then you'll get it as 19+squrt.(362)
hope this helps you

Answer 13

thanks for the medal @amistre64

Answer 14

do you think that there's any other way
if yes , then please let me know

Answer 15

what is a scale??

Answer 16

*** what is a scale ?***
can you be more specific? a scale could mean measures weights, covers a fish, climb a mountain...

for a map, the scale is the ratio of the distance on the map to the distance in the real world

Answer 17

oh! i'm sorry i meant a ruler
i call it as scale
i apologise:)

Answer 18

\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]