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Trigonometry
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find two pairs of polar coordinates for points(1,1) satisfying -2pi
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|dw:1387477693117:dw|
i want to find the polar coordinates
the polar coordinates are \((r,\theta)\)
yes i know how to find r and theta but then the condition -2pi<theta<=0 is to be fullfilled to find polar coordinates??
\[r=\sqrt{x^2+y^2}\] \[\theta = \tan^{-1} \left( \frac {y}{x} \right)\] but theta must be adjusted to fit your criteria, i.e., \(-2\pi<\theta \le 0\)
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look at the point. what would theta be regularly? that is, if 0 < theta < pi/2
as (1,1) is in ist coordinaye should we add and subtract 90 to thete ??
|dw:1387478254427:dw|
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