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What is the solution to x=sqrt(2x+3)
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Square both sides to get rid of the square root.
so let me see if im getting what your saying... so square 2x and 3 right
you have: \(\sf x^2=2x+3\). Which looks like....a polynomial that you can factor.
Remember that \(\sf \sqrt{x} = x^\frac{1}{2}\), so when you square it, you have: \(\sf [x^\frac{1}{2}]^2\) Which is basically \(\sf x^1=x\)
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