Question

use the implicit differentiation to find dy/dx of 4x^2-8xy=y^2-8x

Answer 1

Use the power and product rules :)

Answer 2

Do you know how to do implicit diff tho?

Answer 3

nope

Answer 4

Differentiate with respect to x, what do you get?
you are supposed to find y'

\[\huge 4x^2-8xy=y^2-8x\]
\[\huge 8x - 8y -8xy' = 2yy' -9\]
Group the terms with y' and solve for y'

Answer 5

that should be - 8* at the end

Answer 6

\[\huge 8x - 8y + 8 = y' (8x + 2y)\]
\[\huge \frac{ 8(x-y+1) }{ 8x + 2y } = y'\]
you understand?..