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Mathematics 16 Online
OpenStudy (anonymous):

pic

OpenStudy (anonymous):

@jziggy

OpenStudy (anonymous):

ok, nice pic

OpenStudy (anonymous):

this has me completely lost

OpenStudy (jziggy):

hm... what does LRAM stand for?

OpenStudy (anonymous):

here is a link to a guy that uses LRAM http://answers.yahoo.com/question/index?qid=20100118184917AA1kO61

OpenStudy (jziggy):

Ok, so it's just an approximation using 4 rectangles where you measure them at the left endpoint

OpenStudy (anonymous):

yes

OpenStudy (jziggy):

So we need to divide the interval into 4 sections since n = 4

OpenStudy (anonymous):

k

OpenStudy (jziggy):

We have a rectangle from 0 to 1/4, from 1/4 to 1/2, 1/2 to 3/4 and 3/4 to 1

OpenStudy (anonymous):

yeah

OpenStudy (jziggy):

So now we calculate the height of each rectangle based on the endpoint f(x) = 2x - x^3 f(0) = 0 f(1/4) = 1/2 - 1/64 = 31/64 f(1/2) = 1 - 1/8 = 7/8 = 56/64 f(3/4) = 3/2 - 27/64 = 96/64-27/64 = 69/64 So our left endpoints are 0, 31/64, 56/64, and 69/64

OpenStudy (jziggy):

Now we add all these together and multiply that by delta x

OpenStudy (anonymous):

oh i see :)

OpenStudy (anonymous):

2.4375

OpenStudy (anonymous):

*^X

OpenStudy (jziggy):

(1/4)*(0 + 31/64 + 56/64 + 69/64 )= (156/64)*(1/4) Which simplifies to 39/64

OpenStudy (anonymous):

and thats it

OpenStudy (jziggy):

There ya go, that's all I can help with tonight though 1:12 am is a bit late for me haha

OpenStudy (anonymous):

yeah thank you very much :)

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