Plz help and I dont want just answers...will give medals!!!
The town is organizing a Fourth of July parade. There will be two sizes of floats in the parade( 30 ft and 15 ft). A space of 10 ft will be left after each float.
A. The parade must be at least 150 ft long, but less than 200 ft long. What combinations of large and small floats are possible?
B. Large floats cost $600 to operate. The town has a budget of $2500 to operate the floats. How does this change your answer to part A? What combinations of large and small floats are possible?

Question

Plz help and I dont want just answers...will give medals!!!
The town is organizing a Fourth of July parade. There will be two sizes of floats in the parade( 30 ft and 15 ft). A space of 10 ft will be left after each float.
A. The parade must be at least 150 ft long, but less than 200 ft long. What combinations of large and small floats are possible?
B. Large floats cost $600 to operate. The town has a budget of $2500 to operate the floats. How does this change your answer to part A? What combinations of large and small floats are possible?

jack1 · Answer

stab in the dark here, so bear with me:

A: x = large floats;   y = small floats
40x + 25y = 160 to 210 
combinations are:
5=x and 0=y
4=x and 0=y
4=x and 1=y
4=x and 2=y
3=x and 2=y
3=x and 3=y
2=x and 4=y
2=x and 5=y
1=x nd   5=y
1=x and 6=y

anonymous · Answer

the question is too confusing

anonymous · Answer

where did you get 40 and 25?

anonymous · Answer

tell me about it Sourwing

anonymous · Answer

base on the information, all I can come up is
150 ≤ 30x + 15y + (x+y-1)(10) < 200

jack1 · Answer

5=x and 0=y    = 200 ft
4=x and 0=y    = 160 ft
4=x and 1=y    = 185 ft
4=x and 2=y    = 210 ft
3=x and 2=y    = 170ft
3=x and 3=y    = 195ft
2=x and 4=y    = 180 ft
2=x and 5=y    = 205 ft
1=x nd   5=y    = 165 ft
1=x and 6=y    = 190 ft

x = 40 because 10 ft of space between each float
y = 25 ...ditto

anonymous · Answer

that's is for part A

anonymous · Answer

oh haha i feel dumb...i missed most of my freshman year so im tryin to make up for it

jack1 · Answer

same reason for 160 and 210 ft

jack1 · Answer

i dont know if this line should be included as question says "less than 200 ft" and this one's exactly 200 ft

4=x and 2=y    = 210 ft

anonymous · Answer

Honestly IDFK

jack1 · Answer

lol!
n e ways
Part B:   budget
assuming small floats are free
budget = $2500 = how many large floats max?
2500/600 = 4.166
so 4 max
so any combination above that has more than 5 large floats (x) is out

jack1 · Answer

so i guess ur final answer for B is :

4=x and 0=y
4=x and 1=y

3=x and 2=y
3=x and 3=y
2=x and 4=y
2=x and 5=y
1=x nd   5=y
1=x and 6=y

anonymous · Answer

OMG ur a lifesaver!!! How do I give u a medal?

jack1 · Answer

no worries hey, happy to help, good luck adriana  ;)

anonymous · Answer

Thank you so MUCH!!! And you too....Merry Christmas!