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what is the inverse of y=3x+12? How do i solve this?
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set y to x and x to y and solve for y
so it would look lik x=3y+12?
yup
u must do the inverse of the operations to get what you started with
if you add 12 last and multiplied before that then to get back what u started... you should subtract 12 and divided by 3
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Procedure for finding inverse change f(x) to y switch x and y solve for y the new function is the inverse!
So we got: \[y=3x+12\] Reverse x and y: \[x=3y+12\] Solve for y: \[\begin{array}{rcl}x&=&3y+12\\x-12&=&3y\\\frac{x-12}3&=&y\\y&=&\frac{x-12}3\end{array}\] Therefore its inverse is: \[y=\frac{x-12}3\]
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