Question

Caluculus help?

sketch the graph of the function using
extrema, intercepts, symmetry, and asymptotes.

y=x^2/x^2-9

Answer 1

@Euler271 @kc_kennylau @karatechopper help him, please

Answer 2

Extrema is when y'(x)=0
Intercepts is when x=0 or y=0 or if you're lucky both
Symmetry is when y(x)=y(-x) or x(y)=x(-y)
@Loser66 help him with asymptotes plz

Answer 3

x^2 - 9 = 0 --> x = \(\pm3\) are asymptotes

Answer 4

x = 0, y =0 , the graph must past origin
y ' = \(\dfrac{-18x}{(x^2 - 9)^2}\) therefore y' >0 when x<0 and y'<0 when x>0
so the graph is increase when x<0, decrease when x >0