i will fan & give a medal if you can help me!
divide by 3 first on both the side
okay. i did that. i got square root x + 6 = -4
yes now if you square both the sides and solve for x you will the value for x . Now do you know how to tell if it is a extraneous solution?
\[3\sqrt{x+6}=-12\] Divide both side by 3 \[\sqrt{x+6}=-4\] Squaring both sides \[(\sqrt{x+6})^2=(-4)^2\] \[x+6=16\] Subtract both side by 6 \[x+6-6=16-6\] \[x=10\]
@kendallnicole you can learn about extraneous from here http://www.mathwords.com/e/extraneous_solution.htm
thnx :) is ten extreneous?
Correct
thanks for your help! :))
Anytime.
could you help me with another?
Braxton and Maggie babysit children for extra money over the summer. Braxton's income is determined by f(x) = 9x + 10, where x is the number of hours. Maggie's income is g(x) = 6x + 15. If Braxton and Maggie were to combine their efforts, their income would be h(x) = f(x) + g(x). Assume Braxton works 5 hours. Create the function h(x) and indicate if Braxton will make more money working alone or by teaming with Maggie. h(x) = 15x + 25, work alone h(x) = 3x + 5, work alone h(x) = 3x + 5, team with Maggie h(x) = 15x + 25, team with Maggie
@Nurali
can you write down expression for h(x) ?
idk it:/
k np :) h(x) = f(x) + g(x) now we know f(x) = 9x +10 and g(x) = 6x + 15 put respective values for f(x) and g(x) you will get the expression for h(x)
okay, thank you!
but did you get your answer? It has two parts to it
is it 3x + 5 ?!
NO put h(x) = 9x+10 + 6x+15 can you solve from here?
h(x) = 15x + 25, team with Maggie
?!
Yes h(x) is correct but why will he will team up with Maggie?
i dont know, i guessed aha
aha and I Caught you :) you just want the answer or solution
well i think if he teams up with maggie he'd get more money? im not sure
In the question it say Braxton works for 5 hours so we can calculate money he earns working alone f(5) now money earned working together is h(5). It is not mentioned in the question but to solve we can assume that they will divide money in equal parts so braxton will earn h(5)/2 now solve and get the answer!
so he still makes more money being with the girl right?
Being with the girl has advantages but I guess not in this case :)
f(5) = 55 and h(5)=100
so if hes alone? he makes more?
f(5) = 55 and h(5)/2 = 50 55 > 50 now your call :P
working alone?
Yes...partnering here is not profitable
THANK YOUU SO MUCH.
YOU ARE WELCOME!!
\[x ^{\frac{ 2 }{ 5 }}*x ^{\frac{ 2 }{ 9 }}\] \[x ^{\frac{ 2 }{ 5 }+\frac{ 2 }{ 9 }}\] \[x ^{\frac{ 2*9+2*5 }{ 5*9 }}\] \[x ^{\frac{ 28 }{ 45 }}\]
Last one is correct.
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