Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5,
1 and 1 over 5 …
@ranga
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OpenStudy (kc_kennylau):
1. Find the common difference d.
2. Calculate the value of a+24d (a is the first term)
OpenStudy (kc_kennylau):
rmb each arithmetic sequence has a common difference :)
the first term is a
the second term is a+d
the third term is a+2d
the nth term is a+(n-1)d
OpenStudy (anonymous):
is the common difference is -2/5
OpenStudy (anonymous):
@kc_kennylau
OpenStudy (kc_kennylau):
yes
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OpenStudy (kc_kennylau):
then what's the 25th term?
OpenStudy (anonymous):
Ok hold up.
OpenStudy (kc_kennylau):
ok
OpenStudy (anonymous):
-19 1/5
OpenStudy (anonymous):
@kc_kennylau
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OpenStudy (kc_kennylau):
um no
OpenStudy (anonymous):
umm lol what did i do wrong
OpenStudy (anonymous):
@kc_kennylau
OpenStudy (kc_kennylau):
How did you get your answer?
OpenStudy (anonymous):
never mind let me try agaain i saw my mistake
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OpenStudy (anonymous):
-8
OpenStudy (anonymous):
@kc_kennylau
OpenStudy (kc_kennylau):
nope, you forgot to minus one (a+24d not a+25d)
OpenStudy (anonymous):
ugh so what would it be
OpenStudy (anonymous):
@kc_kennylau
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OpenStudy (anonymous):
i did it with 24 idk what ur talking about @kc_kennylau
OpenStudy (kc_kennylau):
Can you show me your steps? :)
OpenStudy (anonymous):
24*-2/5= -9 3/5+ 1 3/5=-8
OpenStudy (anonymous):
@kc_kennylau can you reply with not having to tag you each time
OpenStudy (kc_kennylau):
sorry i'm doing two questions at once, so please tag me
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OpenStudy (kc_kennylau):
How did you get -9 3/5 and 1 3/5 why are you complicating everything
OpenStudy (anonymous):
pls can you jst show me ur steps @kc_kennylau
OpenStudy (kc_kennylau):
Common difference
=\(1\dfrac35-2\)
=\(\dfrac25\)
The 25th term
=\(a+24d\)
=\(2-24\times\dfrac25\)
=\(2-\dfrac{48}5\)
=\(2-9\dfrac35\)
=\(-\left(9\dfrac35-2\right)\)
=\(-7\dfrac35\)
OpenStudy (anonymous):
so if you dont follow order of operation you would get this wrong?
@kc_kennylau
OpenStudy (kc_kennylau):
oh i see what you did there
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