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Algebra 15 Online
OpenStudy (anonymous):

9. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?

OpenStudy (anonymous):

8. 230 + 230 + 230 + 230 = A. 8120 B. 830 C. 232 D. 230 E. 226

OpenStudy (anonymous):

how do you have two identical questions opened at the same time?

OpenStudy (anonymous):

I answered the 1st question in your other post. the answer to the second question is not one of your options.

OpenStudy (kainui):

@ehuman it's totally the abs.

OpenStudy (anonymous):

@Kainui I didn't understand your comment

OpenStudy (anonymous):

unless it is somehow implied that you need to determine the average...

OpenStudy (anonymous):

oh... abs... lol I didn't see the avatar.

OpenStudy (ranga):

ACBA or ABCA A to C - two possible ways C to B - two possible ways ACBA - four possible ways Similarly, ABCA - four possible ways Total: 8 possible ways.

OpenStudy (anonymous):

What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?

OpenStudy (ranga):

Arithmetic sum = 10(1 + 2 + 3 ..... + 19) = 10 * (1+19)/2 * 19 = 10 * 10 * 19 Mean = sum / how many numbers = 10 * 10 * 19 / 19 = 100

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