Question

Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
a)p2-p1=2*(1=3w)
b)P2 = 2P1 + w
c)P2 = 2P1 + 4w
d)P2 = P1 + w

please help !

Answer 1

The perimeter of a rectangle is given by:
P = 2L + 2W


Let's calculate the first rectangle's perimeter..
it would just be
P_1 = 2L + 2W
Now for the second one:

P_2 = 2(2L) + 2(4w)
P_ 2 = 4L + 8w

Answer 2

I think option C would best full fill this..
\[\Huge P_2 = 2P_1 + 4W\]
\[\Huge P_2 = 2(2L + 2W) + 4w\]
\[\Huge P_2 = 4L + 4W + 4W\]
\[\Huge P_2 = 4L + 8W\]