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OpenStudy (anonymous):
the domain for f(x)=x^2-1 is -3 is less than or equal to x but x is less than or equal to 3. The smallest value in the range of f is
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OpenStudy (kc_kennylau):
\[\text{The domain for }f(x)=x^2-1\text{ is }-3\le x\le3\text{. The smallest value in the range of }f\text{ is?}\]
OpenStudy (kc_kennylau):
Which grade are you in? I need to know what approach I can use :)
OpenStudy (anonymous):
11
:)
OpenStudy (anonymous):
thank you!
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OpenStudy (kc_kennylau):
no problem :)
OpenStudy (anonymous):
OpenStudy (kc_kennylau):
That quadratic equation is a little bit special
OpenStudy (kc_kennylau):
It's both in the standard form and the vertex form
OpenStudy (kc_kennylau):
So you can just use the constant coefficient -1
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OpenStudy (anonymous):
There are many ways to approach this but the first way on the link kennylau provided is the easiest for this type of functions.
OpenStudy (anonymous):
thank you guys!! ^_^
OpenStudy (kc_kennylau):
no problem at all :D
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