Question

am i correct??

The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?


10x + 3y - 1 = 0
x + 3y + 10 = 0
x + 3y - 10 = 0 <<<

Answer 1

yes my friend you're correct :D

Answer 2

^ Like the wise owl said, yes

Answer 3

Since the slope if -1/3 and the y-intercept is 10/3, we can write the equation in slope-intercept form (y=mx+b where m is slope and b is y-intercept):
\[y=-\frac13x+\frac{10}3\]
Then, we can put everything to the left to from the first step of the general solution:
\[y+\frac13x-\frac{10}3=0\]
However, we can't have fractional co-efficient in the general form, so we have to multiply the whole equation by 3: (Math rules suck, right? :P)
\[3y+x-10=0\]
Then, we need to rearrange the terms (ditto):
\[x+3y-10=0\]

Answer 4

Way to type bro

Answer 5

and also for this question am i correct??

Write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7).


x = -3
y = -3
y = 7 <--