The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (-3, 2).
Select one: a. y = -5x + 13 b. y=-1/5x + 7/5 c. y=1/5x - 7/5 d. y=5x- 17
@Nurali
Perpendicular means the negative reciprocal.
ok
So the slope becomes: \[\LARGE 5 ===> -\frac{1}{5}\]
And \[\LARGE y=mx+b\] m=slope b=x-intercept
isn't that the slope formula
Yup, so if you plug in -1/5 you have.. \[\LARGE y=-\frac{1}{5}x+b\] And there's only one answer choice with that slope..
so its b or c
\(\bf \begin{array}{lllll} &x_1&y_1\\ &(-3\quad ,&2) \end{array} \\\quad \\ slope = m= -\cfrac{1}{5} \\ \quad \\ y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)
Made a little mistake, the b is the y-intercept, not x
Well, c has a POSITIVE slope, we need the one with the negative slope
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