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OpenStudy (anonymous):
The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (-3, 2).
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OpenStudy (anonymous):
Select one:
a. y = -5x + 13
b. y=-1/5x + 7/5
c. y=1/5x - 7/5
d. y=5x- 17
OpenStudy (anonymous):
@Nurali
OpenStudy (luigi0210):
Perpendicular means the negative reciprocal.
OpenStudy (anonymous):
ok
OpenStudy (luigi0210):
So the slope becomes:
\[\LARGE 5 ===> -\frac{1}{5}\]
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OpenStudy (luigi0210):
And
\[\LARGE y=mx+b\]
m=slope
b=x-intercept
OpenStudy (anonymous):
isn't that the slope formula
OpenStudy (luigi0210):
Yup, so if you plug in -1/5 you have..
\[\LARGE y=-\frac{1}{5}x+b\]
And there's only one answer choice with that slope..
OpenStudy (anonymous):
so its b or c
OpenStudy (jdoe0001):
\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-3\quad ,&2)
\end{array}
\\\quad \\
slope = m= -\cfrac{1}{5}
\\ \quad \\
y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)
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OpenStudy (luigi0210):
Made a little mistake, the b is the y-intercept, not x
OpenStudy (luigi0210):
Well, c has a POSITIVE slope, we need the one with the negative slope
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