Question

ASAP!!!!! HELLLPPPPPPP!!!!! please! need the answer ASAP

find the 8th term:

Answer 1

\[(2x-4)^{13}\]

Answer 2

@ganeshie8 hey can you please help me get the answer

Answer 3

@BAdhi HELPPP!

Answer 4

by 8th term I guess you are asking the coefficient of the \(x^8\). Use binomial expansion

\((a+b)^n =\displaystyle \sum\limits_{r=0}^n\binom {n}{r}a^rb^{n-r} \)

Answer 5

uhh i dont understand that

Answer 6

Haven't you learned about Binomial theorem?

http://en.wikipedia.org/wiki/Binomial_theorem

Answer 7

you have to find the 8th term of what

Answer 8

every time someone tries to explain this to me i just dont get it I've been trying to get the answer to this problem for the past 2 days

Answer 9

the 8th term of that equation

Answer 10

First, there is no such thing as 8th term in this expression and second, there isn't any equation here. @pinknabastak, i think you want to expand this expression and find the coefficient of the \(x^8\) term am I right?

Answer 11

i guess my teacher didnt explain at all it just says find the 8th term... but i think thats what he wants

Answer 12

hey is this in a book or is it an online one ? either way if u can post a snapshot of the original question it would be lot easy to understand what is missing here

Answer 13

its a worksheet

Answer 14

acually my final test i just didnt take it last year and my teacher gave it to me and told me to finish it this break and hell give me credit for the class for the whole year so its kindaa important to finish it

Answer 15

sorry the pic is backwards

Answer 16

no prob... try this site... http://www.ltcconline.net/greenl/courses/154/seqser/binomial.htm

Answer 17

follow it and u will able to find the 8th term

Answer 18

huh?

Answer 19

just wait i m trying

Answer 20

do u know how to expand an expression
like \[(x + 2)^{2} or ( y + 6)^{3} or (a+x)^{n}\] ?

Answer 21

umm (x+2)(x+2) or (y+6)(y+6)(y+6)

Answer 22

that;s the easy way...

but do u know how to do it like this
(x +y)^2 = x^2 + 2xy + y^2 ?

Answer 23

\[(2x-4)^{13}= [(2x)^{13}]+[13 C 1 *(2x)^{12} *(-4)]+[(2x)^{11}*13C2*(-4)^{2}]---------and so on\]

Answer 24

uh no...is that FOIL?

Answer 25

@nirmalnema what do i do with that?

Answer 26

this is the way of expanding any term in binomial
here nCr = n! / r!(n-r)!
its the combination of terms./.
which i have used..
and you have to do it futher to get the 8 th term

Answer 27

how do i do that?

Answer 28

u have to use the formula of binomial expansion

Answer 29

honestly i have no idea how to use that..can you just tell me the 8th term..cuz obviously you know it and i obviously i cant figure it out and i will MORE then likely never use this again....

Answer 30

according to this the answer will be
\[^{13} C _{7} *(2x)^{6}*(-4)^{7}\] is the 8th term

Answer 31

do i put the C down to...?

Answer 32

what i dont understand what u said

Answer 33

do i write down that whole thing....like whats the "C" for? in the begining of the answer

Answer 34

What grade math is that?

Answer 35

junior/senior class....its Algebra 2

Answer 36

Oh wow, im taking Geometry 9th grade. Sorry I can't help lol

Answer 37

yup you can write it like that also..if you need i can tell you in the simplified form

Answer 38

yes please! :)

Answer 39

@Sally♡ haha yea next year for you

Answer 40

1716 * 64x^7 * (-16384)

Answer 41

THANK YOU SOOOO MUCH!!!

Answer 42

your welcome... :) ....!!!!!!!!!!