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a^2+2b=7 b^2+4c=-7 c^2+ab=-14 then find a^2 + b^2 + c^2
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a^2 + 2b = 7 a^2 = 7 - 2b b^2 + 4c = -7 b^2 = -4c-7 c^2 + ab = -14 c^2 = -ab - 14 go from there
but the answer is given as 14 ..numerical .!
what lesson is this based on?
the chapter is equations ..:/
Probably have to use substitution to solve. Looks gross.
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there are second degree terms too ...substitution will be a lot tiring ..! okay if substituion then how ..approach ?
good luck...
i cant do that ..! so should i close it then
I agree with @shamil98 ...olving three linear equations is bad enough. I'm sure it's doable with substitution. I am not willing to spend time trying to show you how to do it.
even me too ..:/ okay .!
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|dw:1388172530812:dw| this is the answer
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