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Let the limit as x approaches -9; f(x)=9. Find limit as x approaches -9; square root of f(x)
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yes, thats the problem.
No, I mean, use this to find the answer...\[\huge \lim_{x \rightarrow a} \sqrt {f(x) } = \sqrt {\lim_{x \rightarrow a} f(x) }\]
that's exactly how the problem looks still confused
so then it should come as 3 ?
thanks
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You know what \[\huge \lim_{x \rightarrow -9} f(x) = 9\] and this\[\huge \lim_{x \rightarrow -9} \sqrt {f(x) } = \sqrt {\lim_{x \rightarrow -9} f(x) }\]
Understand?
yes thanks man!
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