Calculus help? Please check my work?
A spring is moving up and down according to the function s(t) = -4cos(t).
Part a) Find the first derivative and calculate the velocity of the spring at t =3 pi/4
Part b) Is the spring moving upward or downward at this point? Justify your answer
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OpenStudy (anonymous):
Where is your work to check?
OpenStudy (cggurumanjunath):
v=4sint
OpenStudy (ksaimouli):
(+) up (-) down
OpenStudy (anonymous):
@CGGURUMANJUNATH 4sin t?
OpenStudy (cggurumanjunath):
now put t=3(pi/4)
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OpenStudy (ksaimouli):
That's the derivative
OpenStudy (anonymous):
I thought the derivative of the first function was 0
OpenStudy (cggurumanjunath):
how zero ;can u show ur steps @VIbarguen1
OpenStudy (cggurumanjunath):
it is not zero.
OpenStudy (ksaimouli):
@VIbarguen1 use the product rule , u r right 0 , do second part of product rule
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OpenStudy (anonymous):
no wait you are right. I'm sorry
OpenStudy (anonymous):
Yeah I did the product rule but didn't finish
OpenStudy (ksaimouli):
Sinx=cosx , cosx=-sinx
OpenStudy (anonymous):
so now I insert 3(pi/4)
OpenStudy (cggurumanjunath):
yes
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OpenStudy (anonymous):
that would be 1/sqrt 2 right?
OpenStudy (cggurumanjunath):
4*sin(135)
OpenStudy (cggurumanjunath):
(3*pi)/4=135 degrees
OpenStudy (anonymous):
right so 4* sin (135) = 2/sqrt 2
OpenStudy (cggurumanjunath):
4*sin(135)=2.82
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OpenStudy (anonymous):
ok right sorry. Yeah I have to turn it to decimal
OpenStudy (anonymous):
so th espring is moving upward because it is positive right?
OpenStudy (cggurumanjunath):
yes
OpenStudy (ksaimouli):
Yup, u got it
OpenStudy (anonymous):
Thank you!!
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