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Mathematics 21 Online
OpenStudy (anonymous):

Calculus help? Please check my work? A spring is moving up and down according to the function s(t) = -4cos(t). Part a) Find the first derivative and calculate the velocity of the spring at t =3 pi/4 Part b) Is the spring moving upward or downward at this point? Justify your answer

OpenStudy (anonymous):

Where is your work to check?

OpenStudy (cggurumanjunath):

v=4sint

OpenStudy (ksaimouli):

(+) up (-) down

OpenStudy (anonymous):

@CGGURUMANJUNATH 4sin t?

OpenStudy (cggurumanjunath):

now put t=3(pi/4)

OpenStudy (ksaimouli):

That's the derivative

OpenStudy (anonymous):

I thought the derivative of the first function was 0

OpenStudy (cggurumanjunath):

how zero ;can u show ur steps @VIbarguen1

OpenStudy (cggurumanjunath):

it is not zero.

OpenStudy (ksaimouli):

@VIbarguen1 use the product rule , u r right 0 , do second part of product rule

OpenStudy (anonymous):

no wait you are right. I'm sorry

OpenStudy (anonymous):

Yeah I did the product rule but didn't finish

OpenStudy (ksaimouli):

Sinx=cosx , cosx=-sinx

OpenStudy (anonymous):

so now I insert 3(pi/4)

OpenStudy (cggurumanjunath):

yes

OpenStudy (anonymous):

that would be 1/sqrt 2 right?

OpenStudy (cggurumanjunath):

4*sin(135)

OpenStudy (cggurumanjunath):

(3*pi)/4=135 degrees

OpenStudy (anonymous):

right so 4* sin (135) = 2/sqrt 2

OpenStudy (cggurumanjunath):

4*sin(135)=2.82

OpenStudy (anonymous):

ok right sorry. Yeah I have to turn it to decimal

OpenStudy (anonymous):

so th espring is moving upward because it is positive right?

OpenStudy (cggurumanjunath):

yes

OpenStudy (ksaimouli):

Yup, u got it

OpenStudy (anonymous):

Thank you!!

OpenStudy (cggurumanjunath):

:)

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