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How many solutions are there to the following system of equations? 2x + 6y = 4 5x + 15y = 10
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A. infinitely many B. 0 C. 2 D. 1
divide 1st by 2 divide second by 5
1, Discriminant = 49 - (4*5*3) = -11 2, nemaproblema: x² - 7/5x = -3/5 (x - 7/10)² - 0.49 = -0.6 (x - 7/10)² = -0.11 Both indicates there is no solution.
2x + 6y = 4--->x+3y=2 5x + 15y = 10--->x+3y=2 and now you have 2 variables and one equation second is the same as first
So the answer is A?
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can you go on ?
What do you mean?
yes there is infinite solution
ok Thanks for the help!
when variables are more than equations there is infinite solution
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