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Evaluate the log: \[log_6 \frac{1}{36}\]
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can you try to write 1/36 as the exponent of 6 ?
I can try: 6^(-2)
36 = 6^2 and \(\large \dfrac{1}{a}=a^{-1}\)
YES! thats correct :)
Ok but what does it mean by evaluate? Do I write: \[log_6 \frac{1}{36}=-2\]
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so, \(\large \log_6 6^{-2 } = (-2) \log_66\) because of the property \(\large \log m^n = n \log m\)
yes, -2 is correct!
evaluate means to find the value
Ok thank you :)
welcome ^_^
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