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Beginning with the function f(x)=logax , state which transformations were used to obtain the functions given below: g(x)=loga(3−x)+1 t(x)=2loga3x The "a" is small
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Is that \[\log_a\]or \[\log(a...)\]
the a is small meaning it is subscript jabber
if a is base. \[g \left( x \right)=\log_{a} \left( 3-x \right)+1=\log_{a} \left( 3-x \right)+\log_{a}a= \log_{a}a \left( 3-x \right) \] so if we replace x by a(3-x) we get the reqd.result.
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