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Mathematics 9 Online
OpenStudy (sleepyjess):

Algebra help

OpenStudy (sleepyjess):

\[4 \log _{12}2 + \log _{12}x = \log _{12}96\] x=88 x=80 x=12 x=6

OpenStudy (sleepyjess):

@amoodarya @jdoe0001 @jigglypuff314

OpenStudy (shamil98):

\[\log_b M + \log_b N = \log_b (M*N)\]

OpenStudy (shamil98):

\[\huge \log_b x^n --> n \log_b x\] you can convert the 4log_12 2 using that

OpenStudy (shamil98):

using these rules should make it easier for you to solve.

OpenStudy (sleepyjess):

but none of these answers work with the equation

OpenStudy (shamil98):

Show your work.

OpenStudy (sleepyjess):

\[\log _{b}M + \log _{b}N = \log _{b}(M*N)\] 2*6=12 12=96 x 2*12=24 24=96 x 2*80=160 160=96 x 2*88=176 176=96 x

OpenStudy (shamil98):

no.

OpenStudy (shamil98):

\[4 \log_{12} 2 + \log_{12} x = \log_{12} 96\] \[\log_{12} 2^4 + \log_{12} x = \log_{12} 96\] \[\log_{12} 16x = \log_{12} 96\] \[16x = 96\] so... x = ?

OpenStudy (sleepyjess):

6

OpenStudy (shamil98):

yeah

OpenStudy (sleepyjess):

Ok, thank you. I think I get it now.

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