How many two digit whole numbers are increased by 18 when their digits are reversed? @phi
I look at this and think, what can I easily eliminate? So I ask you, what's your best guess? You have to start somewhere, so take some guesses and I'll help point you in the right direction.
The part that I find confusing is when it says about the number being increased by 18, but then asks about how many of them of are increased?
So all this is saying is suppose you have a number like 12 and reverse the digits, you get 21. That's an increase 9.
Can you explain to me more about how is it increased by 9?
12+9=21
Ok. And then what do i do?
I would write an equation. if you have the "number" ab, it has the value 10a+b it goes up by 18 if you reverse the digits 10a+b+18 = 10b + a
Then you use this nice little example I've laid out for you to think about it and figure it out.
@phi Why is it next to 10 (meaning ab)?
the number 23 has the value 2*10 + 3
Ok
simplify 10a+b+18 = 10b + a to a= b-2 now list all digits that b can be, and find the corresponding a
Would it be 9a+18=9b?
ab - ba= 10a + b - 10b - a = 18 --> 9(a-b) = 18 --> a-b=2. In whole numbers, for example a, with 1 digit, we have totally 10 possible cases (0,1,2,3 ---9) But a and b cannot be equal to 0, then only 9 possible cases left. a - b = 2 which means a > 2 also, therefore a only takes 3 --> 9 (7 possible values) For 7 possible values of a, we have 7 possible values of b. Therefore, totally the answer is we have 7 possible two-digit whole numbers (couples) which reverse for difference of 18 They are: 31 and 13 ; 42 and 24; 53 and 35; 64 and 46; 75 and 57; 86 and 68; 97 and 79
yes, now divide by 9 to get a+2 = b
I guess we have to leave out 02 (+18= 20) because 02 is not a two digit number.
but you can just use b= 0... 9 and toss out the invalid ones. example a+2 = 0 -> a= -2 not allowed...
or start with a=0 ... 9 and find b. Again, toss out invalid numbers a=0--> b=2 but 02 is not allowed because it is not a two digit number.
I don't get about what I should do with a+2=b. Can you example to me this more?
let a=0 ... 9 and find b. using a+2 = b
Like a=1 + 2 and then b=3. 1+2=3
*** Like a=1 + 2 and then b=3. 1+2=3 *** yes. that means your number is 13 if we add 18 to it we should get 31... and we do. so that is one of the solutions
Oh! Can you help me approach all the solutions?while I do the work though. I don't need answers yet :)
just keep going and writing down what you get... (the answers will be "ab" concatenated together)
Ok thanks
start with b= a+2 make a list of all digits a can be 0,1,2... up to 9 for each a digit, write the "b" digit next to it (b is a+2) cross off any combination that does not make sense.
@phi you listed "0" as being a possible digit, but remember that's not possible if these are two digit numbers.
yes, we will cross off 0... but in the beginning I would list all possibilities. First do the mechanical part... then do the "thinking" part
Seems like once you've narrowed it down to a+2=b you've really got a nice clean shot by thinking rather than going through any kind of hardship. a and b are both single digit numbers, so we can finish up by making these extra couple of equations: 0<a<10 0<b<10 And this combined with a+2=b will give you all the information you need.
good point... I was assuming it was self-evident that a and b are restricted to single digits but it is always good to make that explicit.
Ok so I came up to like 32+18=50. That means that that won't work right?
@phi
How did you get 32 ?
3(10)+2=32
make this table a b= a+2 ab 1 3 13 2 4 24 and so on...
Thank you soooooo much. I got my answer as 7. And that was correct!
14 A Mathematica solution is attached.
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