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For the function g(x)=14/(x+3); Find (g^-1 o g)(4) MY options are: 6; 10; 4; 0;
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it is always true that \[(f^{-1}\circ f)(x)=x\]
that is the meaning of the inverse
Okay? I don't see what that has to do with the current question though.
in your case \(x=4\)
How so?
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\[(f^{-1}\circ f)(x)=x\]\[(f^{-1}\circ f)(4)=?\]
I'm not dealing with f's though, it's G...
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