Question

inverse of arctan (x + pi/2)?

Answer 1

\[\tan^{-1} (x+\frac{ \pi }{ 2 })\]

Answer 2

\(\bf tan(\theta)\quad inverse\implies tan^{-1}(\theta)\\ \quad \\
tan^{-1}(\theta)\quad inverse\implies tan(\theta)\\ \quad \\ \quad \\
tan^{-1}\left(x+\frac{\pi}{2}\right)\quad inverse\implies \square ?\)

Answer 3

so I just switch arctan?

Answer 4

I'd think so, yes, since \(\bf tan^{-1}\) is the inverse of \(\bf tan\) and the other way around

Answer 5

okay thank you!

Answer 6

yw

Answer 7

Careful that's not right lmao.