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solve for x: 3/3x+1/x+4=10/7x
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Could you write this with the equation editor so we can see the exact problem you're asking?..
\[\frac{ 3 }{ 3x }+ \frac{ 1 }{ x+4 }= \frac{ 10 }{ 7x }\]
@shamil98
\[\huge \frac{ 3 }{ 3x } + \frac{ 1 }{ x+4 } = \frac{ 10 }{ 7x }\] \[\huge \frac{ 1 }{ x } + \frac{ 1 }{ x+4 } = \frac{ 10 }{ 7x }\] \[\huge \frac{ 1(x+4) + 1(x) }{ x(x+4) } = \frac{ 10 }{ 7x }\] \[\huge \frac{ 2x+4 }{ x^2 + 4x } = \frac{ 10 }{ 7x }\] Cross multiply it now =)
8x and 4x
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Cross multiply the terms... what do you mean 8x and 4x..
\[\huge (2x+4)(7x) = 10(x^2 + 4x)\] Multiply, expand, get everything on one side.
ohh i get for my answer x=-3
@dalia_lam can u help?
u should have 2 answers again
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-3 and 3
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