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what is the solution to the following 3x + 3y = 10 -9x - 9y = -30
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-3*(1)=(2) therefore infinitely many solutions
3(3x+3y = 10) gives 9x + 9y = 30 -9x-9y=-30 we're eliminating here 0 = 0 You have an infinite number of solutions that will work.
The second equation is just the first equation multiplied by -3, hence they are the same equation and you'll have an infinite number of solutions.
3x + 3y = 10 3x = -3y+10 \[x=\frac{ -3y+10 }{ 3 }\]Then substitute this into the 2nd equation
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