Question

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

A.) y = 2x + 6

B.) y = -one halfx + 3

C.)y = -one halfx + 6

D.) y = 2x + 3

Answer 1

What's the slope of the line y = 2x + 2?

Answer 2

I do not understand

Answer 3

The slope is by the x variable when the line is written in slope intercept form y = mx+b.
In the above equation, 2 is the slope

Answer 4

To get a perpendicular line, the slope of the new line must be the opposite inverse of the given line.

The given line has a slope of 2
The line perpendicular to this will be the opposite inverse or -1/2

Answer 5

Now...you want the perpendicular line to pass through the point (6,3). Plug everything into this equation:
y - y1 = m(x-x1) x1. y1
6 3
y - 3 = -1/2(x - 6) now solve
y - 3 = -1/2x + 3
y = -1/2x + 6

This is C in your list

Answer 6

thank you i get it now

Answer 7

good luck