Question

A chemist needs to mix a 12% acid solution with a 32% acid solution to obtain an 8-liters mixture consisting of 20% acid. How many liters of each of teh acid solutions must be used?

Answer 1

please explain answer....

Answer 2

So first do you have any ideas?

Answer 3

I can't figure out what to put as the equation...then i think i got the rest down....

Answer 4

@FibonacciChick666 ??

Answer 5

sorry, uhm so you need to add two quantities to equal 8 liters at .2 conc.

Answer 6

so that means you have 2 variables, the amount of liters of each

Answer 7

so its 12x + 32y =8??

Answer 8

almost you have .12 x+.32 y=.2

Answer 9

because you want to know the ratio required

Answer 10

ait how did you get 2??

Answer 11

0.2

Answer 12

% to decimal

Answer 13

oh from the 20%

Answer 14

ok i think im getting this....

Answer 15

but im confused what do i do next??

Answer 16

yup so now you need a second eq to solve the system. I'm sorry but I have to go I'll check back in like 8 hours sorry.

Answer 17

no please this is the last question i have to answer.....

Answer 18

on my homework i mean...

Answer 19

can you please just tell me the second equation...i think i can figure it out from there....

Answer 20

i don't usually do this but i feel bad leaving x+y=8 I believe

Answer 21

ok now for real i have to go

Answer 22

ok thank you:)

Answer 23

Did ya get it?