Mathematics
6 Online
OpenStudy (anonymous):
Write the expression as a single logarithm
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OpenStudy (anonymous):
\[2\log_{b}+8\log_{b}t\]
OpenStudy (anonymous):
hi :)
OpenStudy (anonymous):
hi
OpenStudy (australopithecus):
You need to memorize two rules.
\[\log(x) + \log(y) = \log(xy)\]
\[-\log(x) = \log(x^{-1})\]
So,
\[\log(x) - \log(y) = \log(\frac{x}{y})\]
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OpenStudy (anonymous):
Lol why are yall saying hi to each other
OpenStudy (australopithecus):
Nice image
OpenStudy (anonymous):
because we're are nice :)
OpenStudy (anonymous):
what image
OpenStudy (anonymous):
but what about the numbers 2 and 8
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OpenStudy (australopithecus):
The list of log rules jdoe0001 posted
OpenStudy (anonymous):
Oh lol that is nice haha
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
yeah it doesn't say anything about what to do with 2 and 8
OpenStudy (australopithecus):
Another log rule
\[\log(x^n) = nlog(x)\]
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OpenStudy (australopithecus):
there you go bs07
OpenStudy (anonymous):
bye :)
OpenStudy (australopithecus):
Jordannyah question hyjacking
OpenStudy (australopithecus):
Highjacking, ugh I can't spell
OpenStudy (australopithecus):
Jordannyah just looking at my posts you should be able to answer that :)
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OpenStudy (anonymous):
@Jordannyah she's wrong don't listen to her XD
OpenStudy (australopithecus):
Yeah that is wrong jordannyah
OpenStudy (anonymous):
I'm sorry @Jordannyah but you are wrong
OpenStudy (australopithecus):
It is a lot of math lies :S
OpenStudy (anonymous):
yes :)
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OpenStudy (australopithecus):
Who's answer?
OpenStudy (australopithecus):
Please review what I wrote @Jordannyah and don't be ashamed to be wrong :) no one is perfect :)