Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

Write the expression as a single logarithm

OpenStudy (anonymous):

\[2\log_{b}+8\log_{b}t\]

OpenStudy (anonymous):

hi :)

OpenStudy (anonymous):

hi

OpenStudy (jdoe0001):

http://www.chilimath.com/algebra/advanced/log/images/466x428xrules,P20of,P20exponents.gif.pagespeed.ic.1z7-Ekl5L5.png <--- use rule 3 there first, then use rule 1

OpenStudy (australopithecus):

You need to memorize two rules. \[\log(x) + \log(y) = \log(xy)\] \[-\log(x) = \log(x^{-1})\] So, \[\log(x) - \log(y) = \log(\frac{x}{y})\]

OpenStudy (anonymous):

Lol why are yall saying hi to each other

OpenStudy (australopithecus):

Nice image

OpenStudy (anonymous):

because we're are nice :)

OpenStudy (anonymous):

what image

OpenStudy (anonymous):

but what about the numbers 2 and 8

OpenStudy (australopithecus):

The list of log rules jdoe0001 posted

OpenStudy (anonymous):

Oh lol that is nice haha

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

yeah it doesn't say anything about what to do with 2 and 8

OpenStudy (australopithecus):

Another log rule \[\log(x^n) = nlog(x)\]

OpenStudy (australopithecus):

there you go bs07

OpenStudy (anonymous):

bye :)

OpenStudy (australopithecus):

Jordannyah question hyjacking

OpenStudy (australopithecus):

Highjacking, ugh I can't spell

OpenStudy (australopithecus):

Jordannyah just looking at my posts you should be able to answer that :)

OpenStudy (anonymous):

@Jordannyah she's wrong don't listen to her XD

OpenStudy (australopithecus):

Yeah that is wrong jordannyah

OpenStudy (anonymous):

I'm sorry @Jordannyah but you are wrong

OpenStudy (australopithecus):

It is a lot of math lies :S

OpenStudy (anonymous):

yes :)

OpenStudy (australopithecus):

Who's answer?

OpenStudy (australopithecus):

Please review what I wrote @Jordannyah and don't be ashamed to be wrong :) no one is perfect :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!