Mark bought 114 meters of fencing to enclose an area of pasture for his sheep. He plans to use all of the fencing to make a rectangle that is twice as long as it is wide.

Use the information you have to create a system of equations. Let l = length and w = width.

Find the length (in meters) of the area he plans to fence.

@texaschic101

Question

Mark bought 114 meters of fencing to enclose an area of pasture for his sheep. He plans to use all of the fencing to make a rectangle that is twice as long as it is wide.

Use the information you have to create a system of equations. Let l = length and w = width.

Find the length (in meters) of the area he plans to fence.

@texaschic101

texaschic101 · Answer

P = 2L + 2W
L = 2W
now sub 2W in for L in the 1st equation
114 = 2(2W) + 2W
114 = 4W + 2W
114 = 6W
114/6 = W
19 = W

L = 2W
L = 2(19)
L = 38

check..
P = 2L + 2W
114 = 2(38) + 2(19)
114 = 76 + 38
114 = 114 (correct)

Length in meters is : 38 meters

anonymous · Answer

You are correct @texaschic101 Thanks! :)

texaschic101 · Answer

anytime Skiller :)

anonymous · Answer

Solve the following for w:$$2(w+2w)=114$$w = 19
2w = 38

anonymous · Answer

(w+2w) is the half perimeter.

Thank you for the medal.