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Rewrite to make it easy to graph using a translation. Describe the graph
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\[\sqrt[3]{27x-81}-5\]
so far i've got (27x-81)^3 -5
is ti powered or sqrt?
is what? its (27x-81) to the power of 3
(3^9)*[(x-3)^3] - 5
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hmmm can you get common factor of 27x and 81 ?
Aim for the form of: \[b \times \sqrt[3]{x-a} - c\] Here is my attempt: \[\sqrt[3]{27x-81}-5\] \[\sqrt[3]{27(x-3)}-5\] \[\sqrt[3]{3^3(x-3)}-5\] \[3\sqrt[3]{(x-3)}-5\] (Okay I have no clue if I did that right, it has been a long time since I did something like this). 3 = Slope. -3 = Horizontal shift (To the right). -5 = Vertical shift (Down five units). Well I tried :3.
@LanguageEnthusiast where'd you get the 3 from instead of 81??
\[27\times3=81\] Like jdoe said, factor :-).
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