Rewrite to make it easy to graph using a translation.
Describe the graph

Question

Rewrite to make it easy to graph using a translation.
Describe the graph

anonymous · Answer

$$\sqrt[3]{27x-81}-5$$

anonymous · Answer

so far i've got (27x-81)^3 -5

anonymous · Answer

is ti powered or sqrt?

anonymous · Answer

is what? its (27x-81) to the power of 3

anonymous · Answer

(3^9)*[(x-3)^3] - 5

jdoe0001 · Answer

hmmm can you get common factor of 27x and 81 ?

anonymous · Answer

Aim for the form of:
$$b \times \sqrt[3]{x-a} - c$$
Here is my attempt:
$$\sqrt[3]{27x-81}-5$$
$$\sqrt[3]{27(x-3)}-5$$
$$\sqrt[3]{3^3(x-3)}-5$$
$$3\sqrt[3]{(x-3)}-5$$
(Okay I have no clue if I did that right, it has been a long time since I did something like this).
3 = Slope.
-3 = Horizontal shift (To the right).
-5 = Vertical shift (Down five units).

Well I tried :3.

anonymous · Answer

@LanguageEnthusiast where'd you get the 3 from instead of 81??

anonymous · Answer

$$27\times3=81$$
Like jdoe said, factor :-).