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Mathematics 7 Online
OpenStudy (anonymous):

Rewrite to make it easy to graph using a translation. Describe the graph

OpenStudy (anonymous):

\[\sqrt[3]{27x-81}-5\]

OpenStudy (anonymous):

so far i've got (27x-81)^3 -5

OpenStudy (anonymous):

is ti powered or sqrt?

OpenStudy (anonymous):

is what? its (27x-81) to the power of 3

OpenStudy (anonymous):

(3^9)*[(x-3)^3] - 5

OpenStudy (jdoe0001):

hmmm can you get common factor of 27x and 81 ?

OpenStudy (anonymous):

Aim for the form of: \[b \times \sqrt[3]{x-a} - c\] Here is my attempt: \[\sqrt[3]{27x-81}-5\] \[\sqrt[3]{27(x-3)}-5\] \[\sqrt[3]{3^3(x-3)}-5\] \[3\sqrt[3]{(x-3)}-5\] (Okay I have no clue if I did that right, it has been a long time since I did something like this). 3 = Slope. -3 = Horizontal shift (To the right). -5 = Vertical shift (Down five units). Well I tried :3.

OpenStudy (anonymous):

@LanguageEnthusiast where'd you get the 3 from instead of 81??

OpenStudy (anonymous):

\[27\times3=81\] Like jdoe said, factor :-).

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