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how to find x for ln(3-x)=1 ??
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is it ln(3)-ln(x)=ln(1) 0-ln(x)=0 ln(x)=0
no its not
so how to do it @rizwan_uet
should i take the base e to remove "ln "
3-x=e^1 x=e^1-3 x=-0.281718 @rizwan_uet
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ln(3-x) = 1 = ln e ln3 - lnx = ln e ln(3/x) = ln e 3/x = e now you can find x
x=3/e x=1.1036 if i substitute x inside ln(3-1.1036) not = to 1 @rizwan_uet
x=0.6399
\( \ln(3-x)=1 \) \( 3-x=e^1 \) \( x=3-e \)
Thanks @ganeshie8
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np :) e is just a number, plug the value of e if u want.
yeah now i know that e=2.7182 @ganeshie8
good :)
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