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jimthompson5910 (jim_thompson5910):
I'm going to use k in place of the blank spot
f(x)= 3x + k
f(-2)= 3(-2) + k ... plug in x = -2 (ie replace every copy of x with -2)
10= 3(-2) + k ... plug in f(-2) = 10 (ie replace every copy of f(-2) with 10)
Now we solve for k
10= 3(-2) + k
10= -6 + k
10+6 = k
16 = k
k = 16
which means that f(x)= 3x + k turns into f(x)= 3x + 16
OpenStudy (anonymous):
thank you, you really made me understand.
jimthompson5910 (jim_thompson5910):
You're welcome. I'm glad to be of help.
OpenStudy (anonymous):
one question, what did you add to get 10 ?
jimthompson5910 (jim_thompson5910):
the 10 is given in the portion where it says "f(-2) = 10"
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jimthompson5910 (jim_thompson5910):
when going from
f(-2)= 3(-2) + k
to
10 = 3(-2) + k
I replaced f(-2) with 10 because it is given that f(-2) = 10