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Mathematics 19 Online
OpenStudy (anonymous):

Solve for x:

OpenStudy (anonymous):

please include the equation :P

OpenStudy (anonymous):

\[e^{x}e^{(x+1)}=1\]

OpenStudy (ddcamp):

This might get you started in the right direction \[e^ae^b=e^{a+b} \\ c^0=1\]

OpenStudy (anonymous):

I know that much I just don't understand how to do the problem at all

OpenStudy (ddcamp):

Use the first rule to simplify the left side of the equation.

OpenStudy (anonymous):

\[e^{x}e^{(x+1)}=e^{x+(x+1)}=e^{x^2+1}\]?

OpenStudy (ddcamp):

x+(x+1) → x+x+1 → 2x+1

OpenStudy (ddcamp):

\[e^{2x+1} = 1 = e^0 \rightarrow e^{2x+1} = e^0 \rightarrow2x+1=0\]

OpenStudy (anonymous):

Then do I solve for x?

OpenStudy (loser66):

yup

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

@Loser66 I love ur profile pic

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