A recessive mutant allele, black causes a very dark body in Drosophila when homozygous. The normal wild-type color is gray. A. A black female is crossed to a heterorozygous gray male. what are the parental genotypes?
What f1 phenotypic and genotypic ratios are produced from this cross? show your punnet square

Question

A recessive mutant allele, black causes a very dark body in Drosophila when homozygous. The normal wild-type color is gray. A. A black female is crossed to a heterorozygous gray male. what are the parental genotypes?
What f1 phenotypic and genotypic ratios are produced from this cross? show your punnet square

wolfe8 · Answer

Hello and welcome to OpenStudy. First, do you know how to construct a punnet square? This might help https://www.youtube.com/watch?v=Y1PCwxUDTl8

anonymous · Answer

yes i do..just need some help setting it up

wolfe8 · Answer

Alright. Let's begin with that alleles you have. Can you list them? Then can you set of that each parent has?

wolfe8 · Answer

Would this post help? http://openstudy.com/study#/updates/52c6746ce4b0fef2cba11148

anonymous · Answer

bb = recessive mutant allele = black
Bb= heterozygous = gray
BB= Homozygous recessive= gray

anonymous · Answer

so i then crossed Bb with bb

anonymous · Answer

is that correct

wolfe8 · Answer

Yes. So then with that, you can follow exactly what the video says around minute 2. Can you try that?

anonymous · Answer

yes i came up with bb= homozygous black = 50%
Bb heterozygous gray= 50%

wolfe8 · Answer

Looks about right to me.

anonymous · Answer

thanks

wolfe8 · Answer

You're welcome and enjoy your stay :)