BC= 15, DC= 28. what is the diameter of circle O to the nearest tenth ?

Question

anonymous · Answer

attachment

anonymous · Answer

HI :D

anonymous · Answer

@jdoe0001 
@jigglypuff314 
@sweetburger 
@KellyN

sweetburger · Answer

i learned geometry long enough to take the test then i forgot

anonymous · Answer

its not a test.. anyways do u know the answer?

sweetburger · Answer

did i say it was a test... i said that i took geometry and only remebered the concepts long enough to take my test then i forgot them at least some of them

jdoe0001 · Answer

attachment

jdoe0001 · Answer

once you find CA, subtract CB from it, and that'd be the diameter BA

anonymous · Answer

whats CA though?

jdoe0001 · Answer

we dunno, but we have the others
ahmm   what would you get for CA from $\bf CD^2=CB\cdot CA \quad ?$

anonymous · Answer

13.1/37.3/52.3/67.3
those are the options

jdoe0001 · Answer

notice, that CD=28, CB=15 thus $\bf CD^2=CB\cdot CA \implies 28^2=15\cdot CA$

anonymous · Answer

idk =/

jdoe0001 · Answer

well.... can you isolate CA?   or "solve for " CA?

anonymous · Answer

784

jdoe0001 · Answer

hmmm.... do you know how to solve linear equations?