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3i(-4−6i)
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distribute it.
idk how man
a(b-c) = ab-ac
use that ^
i^2 = -1
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no i know that, but i don't know how to do it with imaginaries
it's the same thing..
but when i is multiplied i it becomes -1
what is 3i*-4?
\[i = \sqrt{-1} , i^2 = \sqrt{-1} * \sqrt{-1} = -1\]
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im sorry im not sure i get it
3i*-4 = -12i
3i * -6i = -18i^2 i^2 = -1 so -18i^2 = -18 * -1 =18
ans: 18-12i
same old distribution you are used to. the imaginary numbers throws a curve ball at you, but not for long
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oh ok i think i grasp it now, so i^2 is just -1 then,
example |dw:1388704361532:dw|
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