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an airplane is sighted at the same time by two ground observers who are 2 miles apart and in line with the airplane. they report the angles of elevation as 10 degrees and 22 degrees. how high is the airplane?
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Let A, B, C be the position of the first and the second observer and the point directly beneath the airplane. Let H be the height of the air plane. Then we have tan 10deg=h/AC tan 22 deg=h/BC AC-BC=2 This can be solved for the three unknowns h, AC and BC. I find h=0.625 miles. Does that make sense or do you need a further explanation?
further explanation
|dw:1388849825420:dw| that was my drawing
Caroline, Would you mind saying what it is that you'd still like to learn in regard to Kirby's solution?
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