Question

4 6x-4
2+ -- = -----
x+2 x^2-4

Answer 1

Factorize the numerator and the denominator of the second fraction.

Answer 2

@kc_kennylau thank you so much for all the help like honestly

Answer 3

no problem :)

Answer 4

4 2(3x-2)
2+ -- = -------
x+2 (x-2) (x+2)

Answer 5

Make 2 a fraction with denominator being x+2.\(\left(a=\dfrac {ax}x\right)\)

Answer 6

2(x+2) (x-2)
----------
(x+2)(x-2)

Answer 7

you mean:
2(x+2) (x-2) 4 2(3x-2)
----------+---=----------
(x+2)(x-2) x+2 (x-2)(x+2)

Answer 8

does it come out to be

2( x+2) (x-2)+4(x-2)=2x3(x-2)(x+2)
------------
(x+2) (x-2)

Answer 9

no

Answer 10

It comes out to be 2+4(x-2)=2(3x-2)

Answer 11

oh

Answer 12

how did you get that

Answer 13

2(x+2) (x-2) 4 2(3x-2)
----------+---=----------
(x+2)(x-2) x+2 (x-2)(x+2)

2(x+2) (x-2) 4(x-2) 2(3x-2)
----------+---------=----------
(x+2)(x-2) (x+2)(x-2) (x-2)(x+2)

2(x+2)(x-2)+4(x-2)=2(3x-2)

Sorry for my mistake.

Answer 14

why do you loose the denominator in the last step?

Answer 15

I multiplied the whole equation by (x+2)(x-2).

Answer 16

which side of the equation

Answer 17

both.

Answer 18

so that the equality is still valid.

Answer 19

oh then i did this completely wrong

Answer 20

ok so would it be one of those fractional equations that you multiply the denominator toboth sides

Answer 21

ok so i got 2(x+2)(x-2)+4(x-2)=2(3x-2)

Answer 22

yep, that's the same with mine

Answer 23

okay thanks so much