Question

1. Explain how to solve x^2-2x-8>0

Answer 1

\[x^{2}-2x-8>0\]

Answer 2

factor out the equation
set it to zero, and solve for the x

Answer 3

everything good there but the answer

Answer 4

zeros are at \(-2\) and \(4\) and since
\[x^2-2x-8\] is a parabola that faces up, it is negative between the zeros and positive outside of them

Answer 5

you want to know where it is positive, outside the zeros is \(x<-2\) or \(x>4\)

Answer 6

in interval notation \((-\infty, -2)\cup (4,\infty)\)

Answer 7

ya....I just ended it at the solution of x.

Answer 8

Thanks for the help Both of you!