Question

how would you graph (y-2)^2/4-(x+3)^2/9=1?

Answer 1

got a graphing calculator?

Answer 2

yes

Answer 3

http://01.edu-cdn.com/files/static/mcgrawhill-images/9780071439275/f0349-01.jpg

Answer 4

\(\bf \cfrac{(y-2)^2}{4}-\cfrac{(x+3)^2}{9}=1\implies \cfrac{(y-2)^2}{2^2}-\cfrac{(x-(3))^2}{3^2}=1\\ \quad \\
\cfrac{(y-k)^2}{a^2}-\cfrac{(x-h)^2}{b^2}=1\\ \quad \\
center\implies (h,k)\\ \quad \\
\textit{major axis}=a+a\\ \quad \\
\textit{minor axis}=b+b\)