SOLVING SYSTEMS USING SUBSTITUTION!!!! PLEASE HELP!
What are X and Y supposed to be? I'm not good at Algebra... I don't really understand substitution.
y=2x+6
3y-x+3=0
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OpenStudy (anonymous):
First, you turn one of the equations into slope intercept form
OpenStudy (anonymous):
How do i do that though? Sorry, like I said I'm not good at algebra :P
OpenStudy (anonymous):
Its okay. The slope intercept form is y=mx+b
y=2x+6
this equation is already in slope intercept
OpenStudy (anonymous):
next you would plug in what you got for y into the second equation
3y-x+3=0
3(2x+6)-x+3=0 and solve for x
OpenStudy (anonymous):
Oh... Okay that makes sense :)
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OpenStudy (anonymous):
Urgh...sorry The 2x is supposed to be -2x and for the answer I got X=3 and Y=0. Am I right?
OpenStudy (anonymous):
x is right
to get y you plug in what you got for x into the other equation