SOLVING SYSTEMS USING SUBSTITUTION!!!! PLEASE HELP! What are X and Y supposed to be? I'm not good at Algebra... I don't really understand substitution. y=2x+6 3y-x+3=0
First, you turn one of the equations into slope intercept form
How do i do that though? Sorry, like I said I'm not good at algebra :P
Its okay. The slope intercept form is y=mx+b y=2x+6 this equation is already in slope intercept
next you would plug in what you got for y into the second equation 3y-x+3=0 3(2x+6)-x+3=0 and solve for x
Oh... Okay that makes sense :)
Urgh...sorry The 2x is supposed to be -2x and for the answer I got X=3 and Y=0. Am I right?
x is right to get y you plug in what you got for x into the other equation
y=2x+6 y=2(3)+6
Okay. Thanks so much! You really helped :)
anytime :)
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