Question

Which of the following is a solution to the equation log 6 x + log 6 (x + 1) = 1 ?

Answer 1

log6 x - log6 (x-1) =1
log6 (x/(x-1) = 1
6 to the power of one = x/(x-1)
6 = x/(x-1)
6x - 6 = x
5x = 6
x = 6/5 = 1.2

Answer 2

thats not what I put in I said log 6 x **+ log 6 (x **+ 1) = 1

Answer 3

unless that is the same @Jenna_Da_Nerd ..

Answer 4

oops looked at it wrong

Answer 5

hold on

Answer 6

i saw this on another open study question already with the (-)'s @Jenna_Da_Nerd thanks for your help so far though

Answer 7

this isnt the answer though

Answer 8

I know.. If you could help with this one I would appreciate it(:

Answer 9

Subtracting logs means divide so we can combine on the right,

for example:
multiply both sides by x
x(x+1) = 6
arrange as a quadratic equation
x^2 + x - 6 = 0
Factors to
(x+3)(x-2)
Two solutions
x = -3
x = +2, this is the only solution, (we can't find the log of a neg number)
Check this on a calc:
enter: log(2+1) results: .477

Answer 10

just adding that the 1 is log6(6)

Answer 11

thats just an example to help u