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@helder_edwin
What is the center?
can u get the center?
Not sure how?
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\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]
(h,k) is the center.
so to I add the center? OR..
the center is (-10,5). agree?
Yes
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the major axis a=10 and the minor axis b=8, agree?
Yes!
can u compute c? c is the distacne from the center to either focus
there is a relation (an equation) between a, b, and c. do u know it?
ok the relation is \[\large a^2=b^2+c^2 \] then the coordinates of the foci are \[\large (h,k\pm c) \] because the ellipse is vertical
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