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What two inequalities would you use to solve the absolute value inequality |4x + 3| > 2? A. 4x + 3 > -2, 4x + 3 < 2 B. 4x + 3 < -2, 4x + 3 > 2 C. 4x + 3 > 2, 4x – 3 < -2 D. 4x + 3 > 2, 4x + 3 > -2
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Sorry I made a mistake. Let me correct it.
All right, there are two possibilities. The first, 4x + 3 is a positive number; the second, 4x+3 is a negative number, Thus the first inequality is 4x+3>2; the second is 4x+3<-2. So the answer is B.
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